Statistics

Graded: occupation p.235 #3 (1 pt) P 235 #10 (1pt) p. 286 #9 (1pt) Stat 10/Sanchez Hwk 6 answer key p.235, no(prenominal)3.- Four outlook game allow be dealt off the top of a well-shuffled lard. in that respect argon two options: (i) To win $1 if the outset beleaguer is a club, and the plump for is a diamond, and the ordinal is a heart, and the four-spotthly is a spade. (ii) To win $1 if the four crystallize ar of four different events. Which option is better? Or be they the same? Explain. As explained in the textbook on rascal 226 section 2, a deck of cards has 4 suits: clubs, diamonds, hearts, spades. Thre atomic number 18 13 cards in each suit: 2 through 10, jack, queen, king, ace. So in that location ar 4x13=52 cards in the deck. excerpt (i): Prob(the first card is a club, and the second is a diamond, and the third is a heart, and the quaternary is a spade) = Prob( win $1)= (13/52)(13/51)(13/50)(13/49) = 0.00439. Option (ii): Prob(the four cards are o f four different suits) = Prob(winning 1$) = (prob of cosmos of any suit)(prob of being of another suit accustomed that the first (52/52)(39/51)(26/50)(13/49) = 0.10549 Since option (ii) has a higher probability of winning $1, option (ii) is better. Notice how this problem uses conditional probability. p. 235, no. 4.- A poker hand is dealt. visualize the chance that the first four cards are aces and the fifth is a king.

As explained in the textbook on page 226 section 2, a deck of cards has 4 suits: clubs, diamonds, hearts, spades. Thre are 13 cards in each suit: 2 through 10, jack, queen, king, ace. So there ar e 4x13=52 cards in the deck. There are 4 ace! s and 4 kings in a deck of cards. Prob(the first four cards are aces and the fifth is a king)= (4/52)(3/51)(2/50)(1/49)(4/48)= (1/3,000,000). p. 235, no. 5.- One ticket will be drawn at random from the box below. ar color and number strong-minded? Explain. 1 1 8 1 1 8 1 Yes, they are independent. allow C be color and let N be number. Two events are independent if the Prob(N|C) = Prob(N) Is that genuine here? Prob(1|white)=2/3 =Prob(1) =...If you want to get a full essay, install it on our website: OrderCustomPaper.com

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